-rw-r--r-- | libopie2/opiepim/private/opimeventsortvector.cpp | 9 |
1 files changed, 3 insertions, 6 deletions
diff --git a/libopie2/opiepim/private/opimeventsortvector.cpp b/libopie2/opiepim/private/opimeventsortvector.cpp index 4220c63..b85f848 100644 --- a/libopie2/opiepim/private/opimeventsortvector.cpp +++ b/libopie2/opiepim/private/opimeventsortvector.cpp @@ -32,19 +32,17 @@ #include <opie2/opimnotifymanager.h> #include <opie2/odatebookaccess.h> #include <qvaluelist.h> namespace Opie { namespace Internal { -namespace{ - -inline int testAlarmNotifiers( const OPimNotifyManager& leftnotifiers, const OPimNotifyManager& rightnotifiers ){ +int testAlarmNotifiers( const OPimNotifyManager& leftnotifiers, const OPimNotifyManager& rightnotifiers ){ OPimNotifyManager::Alarms left_alarms = leftnotifiers.alarms(); OPimNotifyManager::Alarms right_alarms = rightnotifiers.alarms(); // Well.. How could we compare two lists of alarms? I think we should find the most early datetimes // and compare them.. (se) // Find the first alarm of the left list OPimNotifyManager::Alarms::Iterator it; QDateTime left_earliest; // This datetime is initialized as invalid!! @@ -55,30 +53,29 @@ inline int testAlarmNotifiers( const OPimNotifyManager& leftnotifiers, const OPi } QDateTime right_earliest; // This datetime is initialized as invalid!! for ( it = right_alarms.begin(); it != right_alarms.end(); ++it ){ if ( !right_earliest.isValid() || right_earliest > (*it).dateTime() ){ right_earliest = (*it).dateTime(); } } - int ret; + int ret = 0; // Now compare this found alarms if ( !left_earliest .isValid() ) ret++; if ( !right_earliest.isValid() ) ret--; if ( left_earliest.isValid() && right_earliest.isValid() ){ - ret += left_earliest < right_earliest ? -1 : 1; + left_earliest < right_earliest ? ret-- : ret++; } return ret; } -} OPimEventSortVector::OPimEventSortVector( uint size, bool asc, int sort ) : OPimSortVector<OPimEvent>( size, asc, sort ) {} int OPimEventSortVector::compareItems( const OPimEvent& left, const OPimEvent& right ) { if ( left.uid() == right.uid() ) return 0; |